Distance from San Severino Marche to Lake Oswego
The shortest distance (air line) between San Severino Marche and Lake Oswego is 5,739.76 mi (9,237.25 km).
How far is San Severino Marche from Lake Oswego
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 21:28 (13.12.2025)
Lake Oswego is located in Oregon, United States within 45° 24' 46.44" N -123° 17' 58.56" W (45.4129, -122.7004) coordinates. The local time in Lake Oswego is 12:28 (13.12.2025)
The calculated flying distance from Lake Oswego to Lake Oswego is 5,739.76 miles which is equal to 9,237.25 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Lake Oswego, Oregon, United States