Distance from San Severino Marche to Lexington
The shortest distance (air line) between San Severino Marche and Lexington is 4,820.49 mi (7,757.82 km).
How far is San Severino Marche from Lexington
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 01:51 (14.03.2025)
Lexington is located in Kentucky, United States within 38° 2' 32.28" N -85° 32' 28.68" W (38.0423, -84.4587) coordinates. The local time in Lexington is 19:51 (13.03.2025)
The calculated flying distance from Lexington to Lexington is 4,820.49 miles which is equal to 7,757.82 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Lexington, Kentucky, United States