Distance from San Severino Marche to Lexington Park
The shortest distance (air line) between San Severino Marche and Lexington Park is 4,468.17 mi (7,190.82 km).
How far is San Severino Marche from Lexington Park
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 02:09 (14.03.2025)
Lexington Park is located in Maryland, United States within 38° 15' 10.08" N -77° 33' 27.36" W (38.2528, -76.4424) coordinates. The local time in Lexington Park is 20:09 (13.03.2025)
The calculated flying distance from Lexington Park to Lexington Park is 4,468.17 miles which is equal to 7,190.82 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Lexington Park, Maryland, United States