Distance from San Severino Marche to Lindenwold
The shortest distance (air line) between San Severino Marche and Lindenwold is 4,341.80 mi (6,987.46 km).
How far is San Severino Marche from Lindenwold
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 12:08 (14.12.2025)
Lindenwold is located in New Jersey, United States within 39° 49' 2.28" N -75° 0' 36.72" W (39.8173, -74.9898) coordinates. The local time in Lindenwold is 06:08 (14.12.2025)
The calculated flying distance from Lindenwold to Lindenwold is 4,341.80 miles which is equal to 6,987.46 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Lindenwold, New Jersey, United States