Distance from San Severino Marche to Linlithgow
The shortest distance (air line) between San Severino Marche and Linlithgow is 1,151.85 mi (1,853.73 km).
How far is San Severino Marche from Linlithgow
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 11:28 (28.02.2025)
Linlithgow is located in West Lothian, United Kingdom within 55° 58' 44.76" N -4° 23' 22.2" W (55.9791, -3.6105) coordinates. The local time in Linlithgow is 10:28 (28.02.2025)
The calculated flying distance from Linlithgow to Linlithgow is 1,151.85 miles which is equal to 1,853.73 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Linlithgow, West Lothian, United Kingdom