Distance from San Severino Marche to Montceau-les-Mines
The shortest distance (air line) between San Severino Marche and Montceau-les-Mines is 491.48 mi (790.95 km).
How far is San Severino Marche from Montceau-les-Mines
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 17:08 (16.01.2025)
Montceau-les-Mines is located in Saône-et-Loire, France within 46° 40' 0.84" N 4° 22' 8.04" E (46.6669, 4.3689) coordinates. The local time in Montceau-les-Mines is 17:08 (16.01.2025)
The calculated flying distance from Montceau-les-Mines to Montceau-les-Mines is 491.48 miles which is equal to 790.95 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Montceau-les-Mines, Saône-et-Loire, France