Distance from San Severino Marche to Oranienburg
The shortest distance (air line) between San Severino Marche and Oranienburg is 658.15 mi (1,059.20 km).
How far is San Severino Marche from Oranienburg
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 06:58 (16.03.2025)
Oranienburg is located in Oberhavel, Germany within 52° 45' 15.84" N 13° 14' 12.84" E (52.7544, 13.2369) coordinates. The local time in Oranienburg is 06:58 (16.03.2025)
The calculated flying distance from Oranienburg to Oranienburg is 658.15 miles which is equal to 1,059.20 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Oranienburg, Oberhavel, Germany