Distance from San Severino Marche to Ozarow Mazowiecki
The shortest distance (air line) between San Severino Marche and Ozarow Mazowiecki is 714.06 mi (1,149.17 km).
How far is San Severino Marche from Ozarow Mazowiecki
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 17:37 (12.02.2025)
Ozarow Mazowiecki is located in Warszawski zachodni, Poland within 52° 13' 0.12" N 20° 48' 0" E (52.2167, 20.8000) coordinates. The local time in Ozarow Mazowiecki is 17:37 (12.02.2025)
The calculated flying distance from Ozarow Mazowiecki to Ozarow Mazowiecki is 714.06 miles which is equal to 1,149.17 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Ozarow Mazowiecki, Warszawski zachodni, Poland