Distance from San Severino Marche to Rothenburg ob der Tauber
The shortest distance (air line) between San Severino Marche and Rothenburg ob der Tauber is 448.50 mi (721.79 km).
How far is San Severino Marche from Rothenburg ob der Tauber
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 11:38 (08.02.2025)
Rothenburg ob der Tauber is located in Ansbach; Landkreis, Germany within 49° 22' 59.88" N 10° 10' 59.88" E (49.3833, 10.1833) coordinates. The local time in Rothenburg ob der Tauber is 11:38 (08.02.2025)
The calculated flying distance from Rothenburg ob der Tauber to Rothenburg ob der Tauber is 448.50 miles which is equal to 721.79 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Rothenburg ob der Tauber, Ansbach; Landkreis, Germany