Distance from San Severino Marche to Six-Fours-les-Plages
The shortest distance (air line) between San Severino Marche and Six-Fours-les-Plages is 370.75 mi (596.67 km).
How far is San Severino Marche from Six-Fours-les-Plages
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 15:47 (29.01.2025)
Six-Fours-les-Plages is located in Var, France within 43° 6' 3.24" N 5° 49' 12" E (43.1009, 5.8200) coordinates. The local time in Six-Fours-les-Plages is 15:47 (29.01.2025)
The calculated flying distance from Six-Fours-les-Plages to Six-Fours-les-Plages is 370.75 miles which is equal to 596.67 km.
San Severino Marche, Macerata, Italy
Related Distances from San Severino Marche
Six-Fours-les-Plages, Var, France