Distance from San Vito dei Normanni to Cesky Krumlov
The shortest distance (air line) between San Vito dei Normanni and Cesky Krumlov is 587.36 mi (945.26 km).
How far is San Vito dei Normanni from Cesky Krumlov
San Vito dei Normanni is located in Brindisi, Italy within 40° 39' 20.16" N 17° 42' 12.96" E (40.6556, 17.7036) coordinates. The local time in San Vito dei Normanni is 01:10 (13.01.2025)
Cesky Krumlov is located in Jihočeský kraj, Czechia within 48° 48' 39.96" N 14° 18' 55.08" E (48.8111, 14.3153) coordinates. The local time in Cesky Krumlov is 01:10 (13.01.2025)
The calculated flying distance from Cesky Krumlov to Cesky Krumlov is 587.36 miles which is equal to 945.26 km.
San Vito dei Normanni, Brindisi, Italy
Related Distances from San Vito dei Normanni
Cesky Krumlov, Jihočeský kraj, Czechia