Distance from San Vito dei Normanni to Cesky Tesin
The shortest distance (air line) between San Vito dei Normanni and Cesky Tesin is 629.68 mi (1,013.38 km).
How far is San Vito dei Normanni from Cesky Tesin
San Vito dei Normanni is located in Brindisi, Italy within 40° 39' 20.16" N 17° 42' 12.96" E (40.6556, 17.7036) coordinates. The local time in San Vito dei Normanni is 00:51 (13.01.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 00:51 (13.01.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 629.68 miles which is equal to 1,013.38 km.
San Vito dei Normanni, Brindisi, Italy
Related Distances from San Vito dei Normanni
Cesky Tesin, Moravskoslezský kraj, Czechia