Distance from Sandridge to Aleksandrow Lodzki
The shortest distance (air line) between Sandridge and Aleksandrow Lodzki is 835.26 mi (1,344.23 km).
How far is Sandridge from Aleksandrow Lodzki
Sandridge is located in Hertfordshire, United Kingdom within 51° 46' 50.88" N -1° 41' 46.32" W (51.7808, -0.3038) coordinates. The local time in Sandridge is 08:31 (10.03.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 09:31 (10.03.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 835.26 miles which is equal to 1,344.23 km.
Sandridge, Hertfordshire, United Kingdom
Related Distances from Sandridge
Aleksandrow Lodzki, Łódzki, Poland