Distance from Sandridge to Scherpenheuvel
The shortest distance (air line) between Sandridge and Scherpenheuvel is 233.56 mi (375.88 km).
How far is Sandridge from Scherpenheuvel
Sandridge is located in Hertfordshire, United Kingdom within 51° 46' 50.88" N -1° 41' 46.32" W (51.7808, -0.3038) coordinates. The local time in Sandridge is 12:43 (31.01.2025)
Scherpenheuvel is located in Arr. Leuven, Belgium within 51° 0' 37.08" N 4° 58' 22.08" E (51.0103, 4.9728) coordinates. The local time in Scherpenheuvel is 13:43 (31.01.2025)
The calculated flying distance from Scherpenheuvel to Scherpenheuvel is 233.56 miles which is equal to 375.88 km.
Sandridge, Hertfordshire, United Kingdom
Related Distances from Sandridge
Scherpenheuvel, Arr. Leuven, Belgium