Distance from Sandy Springs to Sveti Ivan Zelina
The shortest distance (air line) between Sandy Springs and Sveti Ivan Zelina is 5,032.55 mi (8,099.11 km).
How far is Sandy Springs from Sveti Ivan Zelina
Sandy Springs is located in Georgia, United States within 33° 56' 11.76" N -85° 37' 46.92" W (33.9366, -84.3703) coordinates. The local time in Sandy Springs is 18:02 (03.01.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 00:02 (04.01.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 5,032.55 miles which is equal to 8,099.11 km.
Sandy Springs, Georgia, United States
Related Distances from Sandy Springs
Sveti Ivan Zelina, Zagrebačka županija, Croatia