Distance from Sankt Polten to Diepenbeek
The shortest distance (air line) between Sankt Polten and Diepenbeek is 493.42 mi (794.09 km).
How far is Sankt Polten from Diepenbeek
Sankt Polten is located in Sankt Pölten, Austria within 48° 12' 0" N 15° 37' 0.12" E (48.2000, 15.6167) coordinates. The local time in Sankt Polten is 06:46 (27.02.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 06:46 (27.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 493.42 miles which is equal to 794.09 km.
Sankt Polten, Sankt Pölten, Austria
Related Distances from Sankt Polten
Diepenbeek, Arr. Hasselt, Belgium