Distance from Sannicandro Garganico to Alexander City
The shortest distance (air line) between Sannicandro Garganico and Alexander City is 5,267.96 mi (8,477.96 km).
How far is Sannicandro Garganico from Alexander City
Sannicandro Garganico is located in Foggia, Italy within 41° 49' 59.88" N 15° 34' 0.12" E (41.8333, 15.5667) coordinates. The local time in Sannicandro Garganico is 11:29 (04.10.2025)
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 04:29 (04.10.2025)
The calculated flying distance from Alexander City to Alexander City is 5,267.96 miles which is equal to 8,477.96 km.
Sannicandro Garganico, Foggia, Italy
Related Distances from Sannicandro Garganico
Alexander City, Alabama, United States