Distance from Sannicandro di Bari to Deerfield Beach
The shortest distance (air line) between Sannicandro di Bari and Deerfield Beach is 5,384.35 mi (8,665.28 km).
How far is Sannicandro di Bari from Deerfield Beach
Sannicandro di Bari is located in Bari, Italy within 41° 0' 0" N 16° 48' 0" E (41.0000, 16.8000) coordinates. The local time in Sannicandro di Bari is 22:44 (09.01.2026)
Deerfield Beach is located in Florida, United States within 26° 18' 18" N -81° 52' 20.28" W (26.3050, -80.1277) coordinates. The local time in Deerfield Beach is 16:44 (09.01.2026)
The calculated flying distance from Deerfield Beach to Deerfield Beach is 5,384.35 miles which is equal to 8,665.28 km.
Sannicandro di Bari, Bari, Italy
Related Distances from Sannicandro di Bari
Deerfield Beach, Florida, United States