Distance from Sannicolau Mare to Alexandroupoli
The shortest distance (air line) between Sannicolau Mare and Alexandroupoli is 446.10 mi (717.93 km).
How far is Sannicolau Mare from Alexandroupoli
Sannicolau Mare is located in Timiş, Romania within 46° 3' 48.96" N 20° 36' 45" E (46.0636, 20.6125) coordinates. The local time in Sannicolau Mare is 18:13 (14.03.2025)
Alexandroupoli is located in Evros, Greece within 40° 51' 0" N 25° 52' 0.12" E (40.8500, 25.8667) coordinates. The local time in Alexandroupoli is 18:13 (14.03.2025)
The calculated flying distance from Alexandroupoli to Alexandroupoli is 446.10 miles which is equal to 717.93 km.
Sannicolau Mare, Timiş, Romania