Distance from Sannicolau Mare to Chaumont-Gistoux
The shortest distance (air line) between Sannicolau Mare and Chaumont-Gistoux is 795.20 mi (1,279.74 km).
How far is Sannicolau Mare from Chaumont-Gistoux
Sannicolau Mare is located in Timiş, Romania within 46° 3' 48.96" N 20° 36' 45" E (46.0636, 20.6125) coordinates. The local time in Sannicolau Mare is 01:06 (24.11.2024)
Chaumont-Gistoux is located in Arr. Nivelles, Belgium within 50° 41' 2.04" N 4° 41' 40.92" E (50.6839, 4.6947) coordinates. The local time in Chaumont-Gistoux is 00:06 (24.11.2024)
The calculated flying distance from Chaumont-Gistoux to Chaumont-Gistoux is 795.20 miles which is equal to 1,279.74 km.
Sannicolau Mare, Timiş, Romania
Related Distances from Sannicolau Mare
Chaumont-Gistoux, Arr. Nivelles, Belgium