Distance from Sansepolcro to Aleksandrow Kujawski
The shortest distance (air line) between Sansepolcro and Aleksandrow Kujawski is 709.14 mi (1,141.24 km).
How far is Sansepolcro from Aleksandrow Kujawski
Sansepolcro is located in Arezzo, Italy within 43° 34' 32.16" N 12° 8' 38.04" E (43.5756, 12.1439) coordinates. The local time in Sansepolcro is 21:27 (13.02.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 21:27 (13.02.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 709.14 miles which is equal to 1,141.24 km.
Related Distances from Sansepolcro
Aleksandrow Kujawski, Włocławski, Poland