Distance from Sansepolcro to Aleksandrow Lodzki
The shortest distance (air line) between Sansepolcro and Aleksandrow Lodzki is 659.04 mi (1,060.62 km).
How far is Sansepolcro from Aleksandrow Lodzki
Sansepolcro is located in Arezzo, Italy within 43° 34' 32.16" N 12° 8' 38.04" E (43.5756, 12.1439) coordinates. The local time in Sansepolcro is 20:57 (13.02.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 20:57 (13.02.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 659.04 miles which is equal to 1,060.62 km.
Related Distances from Sansepolcro
Aleksandrow Lodzki, Łódzki, Poland