Distance from Sansepolcro to Cesky Tesin
The shortest distance (air line) between Sansepolcro and Cesky Tesin is 525.17 mi (845.17 km).
How far is Sansepolcro from Cesky Tesin
Sansepolcro is located in Arezzo, Italy within 43° 34' 32.16" N 12° 8' 38.04" E (43.5756, 12.1439) coordinates. The local time in Sansepolcro is 16:04 (08.11.2024)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 16:04 (08.11.2024)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 525.17 miles which is equal to 845.17 km.
Related Distances from Sansepolcro
Cesky Tesin, Moravskoslezský kraj, Czechia