Distance from Sansepolcro to Janow Lubelski
The shortest distance (air line) between Sansepolcro and Janow Lubelski is 689.06 mi (1,108.93 km).
How far is Sansepolcro from Janow Lubelski
Sansepolcro is located in Arezzo, Italy within 43° 34' 32.16" N 12° 8' 38.04" E (43.5756, 12.1439) coordinates. The local time in Sansepolcro is 01:57 (19.02.2025)
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 01:57 (19.02.2025)
The calculated flying distance from Janow Lubelski to Janow Lubelski is 689.06 miles which is equal to 1,108.93 km.
Related Distances from Sansepolcro
Janow Lubelski, Puławski, Poland