Distance from Sansepolcro to Ozarow Mazowiecki
The shortest distance (air line) between Sansepolcro and Ozarow Mazowiecki is 718.10 mi (1,155.67 km).
How far is Sansepolcro from Ozarow Mazowiecki
Sansepolcro is located in Arezzo, Italy within 43° 34' 32.16" N 12° 8' 38.04" E (43.5756, 12.1439) coordinates. The local time in Sansepolcro is 15:19 (22.02.2025)
Ozarow Mazowiecki is located in Warszawski zachodni, Poland within 52° 13' 0.12" N 20° 48' 0" E (52.2167, 20.8000) coordinates. The local time in Ozarow Mazowiecki is 15:19 (22.02.2025)
The calculated flying distance from Ozarow Mazowiecki to Ozarow Mazowiecki is 718.10 miles which is equal to 1,155.67 km.
Related Distances from Sansepolcro
Ozarow Mazowiecki, Warszawski zachodni, Poland