Distance from Sapulpa to Varnsdorf
The shortest distance (air line) between Sapulpa and Varnsdorf is 5,111.90 mi (8,226.81 km).
How far is Sapulpa from Varnsdorf
Sapulpa is located in Oklahoma, United States within 36° 0' 32.76" N -97° 53' 58.92" W (36.0091, -96.1003) coordinates. The local time in Sapulpa is 00:40 (26.02.2025)
Varnsdorf is located in Ústecký kraj, Czechia within 50° 54' 41.76" N 14° 37' 6.24" E (50.9116, 14.6184) coordinates. The local time in Varnsdorf is 07:40 (26.02.2025)
The calculated flying distance from Varnsdorf to Varnsdorf is 5,111.90 miles which is equal to 8,226.81 km.
Sapulpa, Oklahoma, United States
Related Distances from Sapulpa
Varnsdorf, Ústecký kraj, Czechia