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      Distance from Sapulpa to Villeneuve-la-Garenne

      The shortest distance (air line) between Sapulpa and Villeneuve-la-Garenne is 4,737.58 mi (7,624.40 km).

      How far is Sapulpa from Villeneuve-la-Garenne

      Sapulpa is located in Oklahoma, United States within 36° 0' 32.76" N -97° 53' 58.92" W (36.0091, -96.1003) coordinates. The local time in Sapulpa is 14:58 (01.03.2025)

      Villeneuve-la-Garenne is located in Hauts-de-Seine, France within 48° 56' 13.92" N 2° 19' 40.08" E (48.9372, 2.3278) coordinates. The local time in Villeneuve-la-Garenne is 21:58 (01.03.2025)

      The calculated flying distance from Villeneuve-la-Garenne to Villeneuve-la-Garenne is 4,737.58 miles which is equal to 7,624.40 km.

      Sapulpa, Oklahoma, United States

      Related Distances from Sapulpa

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      Sapulpa to St. Louis (Missouri)369.27 mi (594.28 km)
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      Villeneuve-la-Garenne, Hauts-de-Seine, France

      Related Distances to Villeneuve-la-Garenne