Distance from Sarospatak to Vetraz-Monthoux
The shortest distance (air line) between Sarospatak and Vetraz-Monthoux is 731.97 mi (1,178.00 km).
How far is Sarospatak from Vetraz-Monthoux
Sarospatak is located in Borsod-Abaúj-Zemplén, Hungary within 48° 19' 8.4" N 21° 33' 59.04" E (48.3190, 21.5664) coordinates. The local time in Sarospatak is 20:18 (13.05.2025)
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 20:18 (13.05.2025)
The calculated flying distance from Vetraz-Monthoux to Vetraz-Monthoux is 731.97 miles which is equal to 1,178.00 km.
Sarospatak, Borsod-Abaúj-Zemplén, Hungary
Related Distances from Sarospatak
Vetraz-Monthoux, Haute-Savoie, France