Distance from Sassenburg to Aleksandrow Lodzki
The shortest distance (air line) between Sassenburg and Aleksandrow Lodzki is 370.36 mi (596.04 km).
How far is Sassenburg from Aleksandrow Lodzki
Sassenburg is located in Gifhorn, Germany within 52° 31' 0.12" N 10° 37' 59.88" E (52.5167, 10.6333) coordinates. The local time in Sassenburg is 04:16 (05.03.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 04:16 (05.03.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 370.36 miles which is equal to 596.04 km.
Related Distances from Sassenburg
Aleksandrow Lodzki, Łódzki, Poland