Distance from Savage to Diepenbeek
The shortest distance (air line) between Savage and Diepenbeek is 4,245.04 mi (6,831.73 km).
How far is Savage from Diepenbeek
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 10:51 (24.02.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 17:51 (24.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,245.04 miles which is equal to 6,831.73 km.
Savage, Minnesota, United States
Related Distances from Savage
Diepenbeek, Arr. Hasselt, Belgium