Distance from Savage to Dimitrovgrad
The shortest distance (air line) between Savage and Dimitrovgrad is 5,211.87 mi (8,387.69 km).
How far is Savage from Dimitrovgrad
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 17:25 (02.06.2025)
Dimitrovgrad is located in Pirotska oblast, Serbia within 43° 1' 0.12" N 22° 46' 59.88" E (43.0167, 22.7833) coordinates. The local time in Dimitrovgrad is 00:25 (03.06.2025)
The calculated flying distance from Dimitrovgrad to Dimitrovgrad is 5,211.87 miles which is equal to 8,387.69 km.
Savage, Minnesota, United States
Related Distances from Savage
Dimitrovgrad, Pirotska oblast, Serbia