Distance from Sayreville to Novy Jicin
The shortest distance (air line) between Sayreville and Novy Jicin is 4,262.97 mi (6,860.59 km).
How far is Sayreville from Novy Jicin
Sayreville is located in New Jersey, United States within 40° 27' 56.16" N -75° 40' 34.68" W (40.4656, -74.3237) coordinates. The local time in Sayreville is 20:37 (25.02.2025)
Novy Jicin is located in Moravskoslezský kraj, Czechia within 49° 35' 39.84" N 18° 0' 37.08" E (49.5944, 18.0103) coordinates. The local time in Novy Jicin is 02:37 (26.02.2025)
The calculated flying distance from Novy Jicin to Novy Jicin is 4,262.97 miles which is equal to 6,860.59 km.
Sayreville, New Jersey, United States
Related Distances from Sayreville
Novy Jicin, Moravskoslezský kraj, Czechia