Distance from Sayville to Lyaskovets
The shortest distance (air line) between Sayville and Lyaskovets is 4,754.74 mi (7,652.01 km).
How far is Sayville from Lyaskovets
Sayville is located in New York, United States within 40° 44' 52.08" N -74° 54' 57.6" W (40.7478, -73.0840) coordinates. The local time in Sayville is 09:02 (25.02.2025)
Lyaskovets is located in Veliko Tarnovo, Bulgaria within 43° 6' 0" N 25° 43' 0.12" E (43.1000, 25.7167) coordinates. The local time in Lyaskovets is 16:02 (25.02.2025)
The calculated flying distance from Lyaskovets to Lyaskovets is 4,754.74 miles which is equal to 7,652.01 km.
Sayville, New York, United States
Related Distances from Sayville
Lyaskovets, Veliko Tarnovo, Bulgaria