Distance from Schenefeld to Mercato San Severino
The shortest distance (air line) between Schenefeld and Mercato San Severino is 915.08 mi (1,472.68 km).
How far is Schenefeld from Mercato San Severino
Schenefeld is located in Pinneberg, Germany within 53° 36' 10.08" N 9° 49' 23.88" E (53.6028, 9.8233) coordinates. The local time in Schenefeld is 17:22 (28.05.2025)
Mercato San Severino is located in Salerno, Italy within 40° 46' 59.88" N 14° 46' 0.12" E (40.7833, 14.7667) coordinates. The local time in Mercato San Severino is 17:22 (28.05.2025)
The calculated flying distance from Mercato San Severino to Mercato San Severino is 915.08 miles which is equal to 1,472.68 km.
Schenefeld, Pinneberg, Germany
Related Distances from Schenefeld
Mercato San Severino, Salerno, Italy