Distance from Seabrook to Aleksandrovac
The shortest distance (air line) between Seabrook and Aleksandrovac is 4,781.37 mi (7,694.88 km).
How far is Seabrook from Aleksandrovac
Seabrook is located in Maryland, United States within 38° 58' 48.72" N -77° 8' 59.28" W (38.9802, -76.8502) coordinates. The local time in Seabrook is 08:41 (06.06.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 14:41 (06.06.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 4,781.37 miles which is equal to 7,694.88 km.
Seabrook, Maryland, United States
Related Distances from Seabrook
Aleksandrovac, Rasinska oblast, Serbia