Distance from Seabrook to Aleksandrow Kujawski
The shortest distance (air line) between Seabrook and Aleksandrow Kujawski is 4,342.86 mi (6,989.16 km).
How far is Seabrook from Aleksandrow Kujawski
Seabrook is located in Maryland, United States within 38° 58' 48.72" N -77° 8' 59.28" W (38.9802, -76.8502) coordinates. The local time in Seabrook is 05:15 (24.05.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 11:15 (24.05.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 4,342.86 miles which is equal to 6,989.16 km.
Seabrook, Maryland, United States
Related Distances from Seabrook
Aleksandrow Kujawski, Włocławski, Poland