Distance from Seabrook to Aleksandrow Lodzki
The shortest distance (air line) between Seabrook and Aleksandrow Lodzki is 4,401.72 mi (7,083.88 km).
How far is Seabrook from Aleksandrow Lodzki
Seabrook is located in Maryland, United States within 38° 58' 48.72" N -77° 8' 59.28" W (38.9802, -76.8502) coordinates. The local time in Seabrook is 10:27 (24.05.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 16:27 (24.05.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,401.72 miles which is equal to 7,083.88 km.
Seabrook, Maryland, United States
Related Distances from Seabrook
Aleksandrow Lodzki, Łódzki, Poland