Distance from Seabrook to Mercato San Severino
The shortest distance (air line) between Seabrook and Mercato San Severino is 4,613.94 mi (7,425.42 km).
How far is Seabrook from Mercato San Severino
Seabrook is located in Maryland, United States within 38° 58' 48.72" N -77° 8' 59.28" W (38.9802, -76.8502) coordinates. The local time in Seabrook is 19:48 (18.05.2025)
Mercato San Severino is located in Salerno, Italy within 40° 46' 59.88" N 14° 46' 0.12" E (40.7833, 14.7667) coordinates. The local time in Mercato San Severino is 01:48 (19.05.2025)
The calculated flying distance from Mercato San Severino to Mercato San Severino is 4,613.94 miles which is equal to 7,425.42 km.
Seabrook, Maryland, United States
Related Distances from Seabrook
Mercato San Severino, Salerno, Italy