Distance from Seagoville to Lyaskovets
The shortest distance (air line) between Seagoville and Lyaskovets is 6,058.01 mi (9,749.43 km).
How far is Seagoville from Lyaskovets
Seagoville is located in Texas, United States within 32° 39' 10.8" N -97° 27' 15.84" W (32.6530, -96.5456) coordinates. The local time in Seagoville is 17:28 (07.11.2024)
Lyaskovets is located in Veliko Tarnovo, Bulgaria within 43° 6' 0" N 25° 43' 0.12" E (43.1000, 25.7167) coordinates. The local time in Lyaskovets is 01:28 (08.11.2024)
The calculated flying distance from Lyaskovets to Lyaskovets is 6,058.01 miles which is equal to 9,749.43 km.
Seagoville, Texas, United States
Related Distances from Seagoville
Lyaskovets, Veliko Tarnovo, Bulgaria