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      Distance from Seagoville to Voisins-le-Bretonneux

      The shortest distance (air line) between Seagoville and Voisins-le-Bretonneux is 4,917.45 mi (7,913.87 km).

      How far is Seagoville from Voisins-le-Bretonneux

      Seagoville is located in Texas, United States within 32° 39' 10.8" N -97° 27' 15.84" W (32.6530, -96.5456) coordinates. The local time in Seagoville is 15:30 (03.03.2025)

      Voisins-le-Bretonneux is located in Yvelines, France within 48° 45' 29.88" N 2° 3' 2.88" E (48.7583, 2.0508) coordinates. The local time in Voisins-le-Bretonneux is 22:30 (03.03.2025)

      The calculated flying distance from Voisins-le-Bretonneux to Voisins-le-Bretonneux is 4,917.45 miles which is equal to 7,913.87 km.

      Seagoville, Texas, United States

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      Voisins-le-Bretonneux, Yvelines, France

      Related Distances to Voisins-le-Bretonneux