Distance from Secaucus to Aartselaar
The shortest distance (air line) between Secaucus and Aartselaar is 3,652.56 mi (5,878.22 km).
How far is Secaucus from Aartselaar
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 04:51 (24.02.2025)
Aartselaar is located in Arr. Antwerpen, Belgium within 51° 7' 59.88" N 4° 22' 59.88" E (51.1333, 4.3833) coordinates. The local time in Aartselaar is 10:51 (24.02.2025)
The calculated flying distance from Aartselaar to Aartselaar is 3,652.56 miles which is equal to 5,878.22 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Aartselaar, Arr. Antwerpen, Belgium