Distance from Secaucus to Assebroek
The shortest distance (air line) between Secaucus and Assebroek is 3,605.09 mi (5,801.83 km).
How far is Secaucus from Assebroek
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 10:36 (24.02.2025)
Assebroek is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 15' 0" E (51.2000, 3.2500) coordinates. The local time in Assebroek is 16:36 (24.02.2025)
The calculated flying distance from Assebroek to Assebroek is 3,605.09 miles which is equal to 5,801.83 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Assebroek, Arr. Brugge, Belgium