Distance from Secaucus to Aubergenville
The shortest distance (air line) between Secaucus and Aubergenville is 3,603.25 mi (5,798.88 km).
How far is Secaucus from Aubergenville
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 01:36 (28.04.2025)
Aubergenville is located in Yvelines, France within 48° 57' 29.88" N 1° 51' 18" E (48.9583, 1.8550) coordinates. The local time in Aubergenville is 07:36 (28.04.2025)
The calculated flying distance from Aubergenville to Aubergenville is 3,603.25 miles which is equal to 5,798.88 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Aubergenville, Yvelines, France