Distance from Secaucus to Begijnendijk
The shortest distance (air line) between Secaucus and Begijnendijk is 3,671.69 mi (5,909.01 km).
How far is Secaucus from Begijnendijk
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 12:53 (24.02.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 18:53 (24.02.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 3,671.69 miles which is equal to 5,909.01 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Begijnendijk, Arr. Leuven, Belgium