Distance from Secaucus to Boortmeerbeek
The shortest distance (air line) between Secaucus and Boortmeerbeek is 3,663.78 mi (5,896.28 km).
How far is Secaucus from Boortmeerbeek
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 12:56 (24.02.2025)
Boortmeerbeek is located in Arr. Leuven, Belgium within 50° 58' 59.88" N 4° 34' 0.12" E (50.9833, 4.5667) coordinates. The local time in Boortmeerbeek is 18:56 (24.02.2025)
The calculated flying distance from Boortmeerbeek to Boortmeerbeek is 3,663.78 miles which is equal to 5,896.28 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Boortmeerbeek, Arr. Leuven, Belgium