Distance from Secaucus to Buggenhout
The shortest distance (air line) between Secaucus and Buggenhout is 3,648.52 mi (5,871.73 km).
How far is Secaucus from Buggenhout
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 12:49 (24.02.2025)
Buggenhout is located in Arr. Dendermonde, Belgium within 51° 0' 0" N 4° 12' 0" E (51.0000, 4.2000) coordinates. The local time in Buggenhout is 18:49 (24.02.2025)
The calculated flying distance from Buggenhout to Buggenhout is 3,648.52 miles which is equal to 5,871.73 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Buggenhout, Arr. Dendermonde, Belgium