Distance from Secaucus to Kalmthout
The shortest distance (air line) between Secaucus and Kalmthout is 3,649.61 mi (5,873.48 km).
How far is Secaucus from Kalmthout
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 13:16 (23.04.2025)
Kalmthout is located in Arr. Antwerpen, Belgium within 51° 22' 59.88" N 4° 28' 0.12" E (51.3833, 4.4667) coordinates. The local time in Kalmthout is 19:16 (23.04.2025)
The calculated flying distance from Kalmthout to Kalmthout is 3,649.61 miles which is equal to 5,873.48 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Kalmthout, Arr. Antwerpen, Belgium