Distance from Secaucus to Kampenhout
The shortest distance (air line) between Secaucus and Kampenhout is 3,664.16 mi (5,896.89 km).
How far is Secaucus from Kampenhout
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 20:59 (24.02.2025)
Kampenhout is located in Arr. Halle-Vilvoorde, Belgium within 50° 56' 28.68" N 4° 32' 58.56" E (50.9413, 4.5496) coordinates. The local time in Kampenhout is 02:59 (25.02.2025)
The calculated flying distance from Kampenhout to Kampenhout is 3,664.16 miles which is equal to 5,896.89 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Kampenhout, Arr. Halle-Vilvoorde, Belgium