Distance from Secaucus to Lappersdorf
The shortest distance (air line) between Secaucus and Lappersdorf is 4,022.83 mi (6,474.12 km).
How far is Secaucus from Lappersdorf
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 14:48 (31.05.2025)
Lappersdorf is located in Regensburg; Landkreis, Germany within 49° 3' 9" N 12° 5' 25.08" E (49.0525, 12.0903) coordinates. The local time in Lappersdorf is 20:48 (31.05.2025)
The calculated flying distance from Lappersdorf to Lappersdorf is 4,022.83 miles which is equal to 6,474.12 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Lappersdorf, Regensburg; Landkreis, Germany