Distance from Secaucus to Lovendegem
The shortest distance (air line) between Secaucus and Lovendegem is 3,621.73 mi (5,828.61 km).
How far is Secaucus from Lovendegem
Secaucus is located in New Jersey, United States within 40° 46' 51.6" N -75° 56' 2.76" W (40.7810, -74.0659) coordinates. The local time in Secaucus is 22:46 (24.02.2025)
Lovendegem is located in Arr. Gent, Belgium within 51° 6' 0" N 3° 36' 0" E (51.1000, 3.6000) coordinates. The local time in Lovendegem is 04:46 (25.02.2025)
The calculated flying distance from Lovendegem to Lovendegem is 3,621.73 miles which is equal to 5,828.61 km.
Secaucus, New Jersey, United States
Related Distances from Secaucus
Lovendegem, Arr. Gent, Belgium